Question

If $sinx+cosecx=2$, then $si{n}^{n}x+cose{c}^{n}x$ is equal to

[UPSEAT 2002]

• A. 2
• B. 1
• C.
• D.

Answer 1

The correct option is A

2

$sinx+cosecx=2\Rightarrow (sinx-1{)}^2=0\Rightarrow sinx=1$
$\therefore si{n}^x+cose{c}^{n}x=1+1=2$