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Question

If sixth term of a H.P. is 161 and its tenth term is 1105, then first term of that H.P. is


A

128

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B

139

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C

16

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D

117

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Solution

The correct option is C

16


T6 of H.P. = 161T6 of A.P. = 61

and T10 of H.P. = 1105T10 of A.P. = 105,

so, a + 5d = 61 ........(i) and a + 9d = 105 .....(ii)

From (i) and (ii), a= 6

Therefore first term of H.P. = 1a = 16.


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