Question

If solubility of $AgCl$ in $0.2M$ solution of $AgN{O}_3$ is represented as $Y\times {10}^{-10}$, then the value of $Y$ is ________.

[Given: $K_{sp\left(AgCl\right)}={10}^{-10}$]

Answer 1

Th expression for the solubility product for $AgCl$ is $K_{sp}=\left[A{g}^{+}\right]\left[C{l}^{-}\right]$

But $K_{sp}=1\times {10}^{-10},\left[A{g}^{+}\right]=0.2M$ and $\left[C{l}^{-}\right]=Y\times {10}^{-10}M$

Substitute values in the above expression:

$1\times {10}^{-10}=0.2\times Y\times {10}^{-10}$.

Hence, $Y=\frac{1}{0.2}=5$

Hence, the value of $Y$ is $5$.