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Standard XII

Chemistry

Common Ion Effect

If solubility...

Question

If solubility product of $Z r_{3} (P O_{4})) 4$ is denoted by $K_{s p}$ and its molar solubility is denoted by S, then which of the following relation between S and $K_{s p}$ is correct?

S = {(\frac{K_{s p}}{144})}^{1 / 6}

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S = {(\frac{K_{s p}}{6912})}^{1 / 7}

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S = {(\frac{K_{s p}}{929})}^{1 / 9}

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S = {(\frac{K_{s p}}{216})}^{1 / 7}

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Solution

The correct option is B $S = {(\frac{K_{s p}}{6912})}^{1 / 7}$
$Z r_{3} (P O_{4})_{4} (s) ⇌ 3 Z r^{4 +} (a q .) 3 S + 4 P O_{4}^{3 -} 4 S (a q .$
Solubility product is given by
$K_{s p} = [Z r^{4 +}]^{3} [P O_{4}^{3 -}]^{4}$
$K_{s p} = (3 S)^{3} (4 S)^{4}$
$K_{s p} = 6912 S^{7}$
$S = {(\frac{K_{s p}}{6912})}^{1 / 7}$

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Similar questions

Q. If thesolubility product of

Z r_{3} (P O_{4})_{4}

is denoted by

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, and its molar solubility is denoted by

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, then which of the following relation between

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is correct?

Q. Consider a sparingly soluble salt, zirconium phosphate

[Z r_{3} (P O_{4})_{4}]

. If molar solubility of zirconium phosphate is denoted by

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is denoted by

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and its molar solubility is denoted by S, then which of the following relation between S and

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is correct?

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is denoted by

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, and its molar solubility is denoted by

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, then which of the following relation between

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and

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Q. Zirconium phosphate

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Common Ion Effect

Standard XII Chemistry

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If solubility product of Zr3(PO4))4 is denoted by Ksp and its molar solubility is denoted by S, then which of the following relation between S and Ksp is correct?

The correct option is B S=(Ksp6912)1/7Zr3(PO4)4(s)⇌3Zr4+(aq.)3S+4PO3−44S(aq. Solubility product is given by Ksp=[Zr4+]3[PO3−4]4 Ksp=(3S)3(4S)4 Ksp=6912 S7 S=(Ksp6912)1/7

If solubility product of $Z r_{3} (P O_{4})) 4$ is denoted by $K_{s p}$ and its molar solubility is denoted by S, then which of the following relation between S and $K_{s p}$ is correct?