If solubility product of Zr3(PO4)4 is denoted by Ksp and its molar solubility is denoted by S, then which of the following relation between S and Ksp is correct?
A
S=(Ksp144)1/6
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B
S=(Ksp6912)1/7
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C
S=(Ksp929)1/9
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D
S=(Ksp216)1/7
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Solution
The correct option is BS=(Ksp6912)1/7 Zr3(PO4)4(s)⇌3Zr4+(aq.)3S+4PO3−44S(aq.)
Solubility product is given by Ksp=[Zr4+]3[PO3−4]4 Ksp=(3S)3(4S)4 Ksp=6912S7 S=(Ksp6912)1/7