If some moles of $O_{2}$ diffuse in 18 sec and same moles of other gas diffuse in 45 sec then what is the molecular weight of the unknown gas

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Solution

The correct option is A

$r_{O_{2}} = \frac{x}{18} m o l e / s e c \Rightarrow r_{8} = \frac{x}{45} m o l / s e c$

$M_{g} = M_{O_{2}} (\frac{r_{O_{2}}}{r_{g}})^{2} = 32 (\frac{x}{18} \times \frac{45}{x})^{2} = 32 \times \frac{45^{2}}{18^{2}}$

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Similar questions

If some moles of $O_{2}$ diffuses in 18 sec and same moles of other gas diffuses in 45 sec.Find the molecular weight of the unknown gas .

If some moles of $O_{2}$ diffuse in 18 sec and same moles of other gas diffuse in 45 sec then what is the molecular weight of the unknown gas

O_{2}

18

45

$ 452 # %

(- 45)^{2}

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