Question

If speed $V$, area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus will be :

• A. $F{A}^2{V}^{-1}$
• B. $F{A}^2{V}^{-3}$
• C. $F{A}^2{V}^{-2}$
• D. $F{A}^{-1}{V}^0$

Answer 1

The correct option is D $F{A}^{-1}{V}^0$

$\text{Young's modulus,}Y=\frac{\text{stress}}{\text{strain}}$

$\Rightarrow Y=\frac{\left(\frac{F}{A}\right)}{\left(\frac{\Delta l}{l_0}\right)}=F{A}^{-1}{V}^0$.

Hence, option $\left(D\right)$ is correct.