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Question

If 1cosx=sinx, then x is equal to , where n ϵ I

A
(2n+1)π2
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B
2nπ+π/4 or nπ
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C
nπ or (2n+1)π4
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D
none of these
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Solution

The correct option is C (2n+1)π2
Given 1cosx=sinx
Squaring on both sides
1cosx=sin2x
1cosx=1cos2x
(1cosx)=(1cosx)(1+cosx)
So cosx=0 or cosx=1
x=(2n+1)π2 or 2nπ

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