Question

If $\sqrt{1+\frac{27}{169}}=1+\frac{x}{13}$, what is the value of 'x'?

• A. $1$
• B. $14$
• C. $10$
• D. $12$

Answer 1

The correct option is A $1$

$\sqrt{1+\frac{27}{169}}=1+\frac{x}{13}$

$⟹\sqrt{\frac{169+27}{169}}=1+\frac{x}{13}$

$⟹\frac{14}{13}=1+\frac{x}{13}$

$⟹\frac{14}{13}-1=\frac{x}{13}$

$⟹\frac{1}{13}=\frac{x}{13}$

$⟹x=1$