Question

If $\sqrt{1+\frac{27}{169}}=1+\frac{x}{13}$, then the value of $x$ is

• A. 1
• B. 14
• C. Cannot be determined
• D. None of these

Answer 1

The correct option is A 1

$\sqrt{1+\frac{27}{169}}=\frac{196}{169}=\frac{14}{13}$
$\Rightarrow 1\frac{1}{13}=1+\frac{1}{13}$
$\therefore x=1$