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Question

If 1x2n+1y2n=a(xnyn) then 1x2n1y2n.dydx=


A

1

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B

xy

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C

xn1yn1

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D

yx

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Solution

The correct option is C

xn1yn1


Let xn=sin A;yn=sin B
After simplification, we get
sin1(xn)sin1(yn)=2 cot1(a)
diff. on both sides w.r.t.'x', we get
nxn11x2n11y2n.nyn1.dydx=0dydx=xn1yn1.1y2n1x2n


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