Question

If $\sqrt{1369}+\sqrt{0.0615+x}=37.25$. Find the value of $x$.

• A. ${10}^{-1}$
• B. ${10}^{-2}$
• C. ${10}^{-3}$
• D. $10$

Answer 1

The correct option is C

${10}^{-3}$

$\sqrt{1369}+\sqrt{0.0615+x}=37.25$
$\Rightarrow \sqrt{0.0615+x}=37.25-\sqrt{1369}$
$\Rightarrow \sqrt{0.0615+x}=37.25-37=0.25$
$\Rightarrow 0.0615+x=(0.25{)}^2=0.0625$
$\Rightarrow x=0.001=\frac{1}{{10}^3}={10}^{-3}$