Question

If $\sqrt{1849}+\sqrt{0.06+x^2}=43.25$, then x is

• A. 0.0025
• B. 0.015
• C. 0.05
• D. 0.025
• E. None of these

Answer 1

The correct option is C

0.05

$\begin{array}{c}43+\sqrt{0.06+x^2}=43.25\Rightarrow \sqrt{0.06+x^2}=0.25\Rightarrow x^2=0.0625-0.06\\ x=\sqrt{0.0025}=0.05\end{array}$