Question

If $\sqrt{2}=1.4142$, then the value of $\sqrt{6}-\sqrt{3}$ up to three places of decimal is

• A. $1.414$
• B. $0.235$
• C. $0.717$
• D. $0.471$

Answer 1

The correct option is C $0.717$

Given: $\sqrt{2}=1.4142$

To find: $\sqrt{6}-\sqrt{3}$

Consider $\sqrt{6}-\sqrt{3}$

$=\sqrt{3}\times \sqrt{2}-\sqrt{3}(\sqrt{6}\text{can be written as}\sqrt{2}\times \sqrt{3})$

$=\sqrt{3}(\sqrt{2}-1)$

$=1.732(1.4142-1)$

$=1.732\left(0.4142\right)$

$=0.717$

$\therefore \left(b\right)$ is the Correct Option