If - 2 - 1 - 414- then find the value of - - 8 - - 50 - - 72 - - 98

√( 8 ) + √( 50 ) + √( 72 ) + √( 98 ) Let us simplify the expression, √( 8 ) + √( 50 ) + √( 72 ) + √( 98 ) = √((2×4)) + √((2×25)) + √((2×36)) + √(( ...

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Byju's Answer

Standard VIII

Mathematics

Terms

If √ 2 = 1 ...

Question

If $\sqrt{2} = 1 \cdot 414,$ then find the value of :
$\sqrt{8} + \sqrt{50} + \sqrt{72} + \sqrt{98}$

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Solution

$\sqrt{8} + \sqrt{50} + \sqrt{72} + \sqrt{98}$
Let us simplify the expression,
$\sqrt{8} + \sqrt{50} + \sqrt{72} + \sqrt{98}$
$= \sqrt{(2 \times 4)} + \sqrt{(2 \times 25)} + \sqrt{(2 \times 36)} + \sqrt{(2 \times 49)}$
$= \sqrt{2} \sqrt{4} + \sqrt{2} \sqrt{25} + \sqrt{2} \sqrt{36} + \sqrt{2} \sqrt{49}$
$= 2 \sqrt{2} + 5 \sqrt{2} + 6 \sqrt{2} + 7 \sqrt{2}$
$= 20 \sqrt{2}$
$= 20 \times 1.414$
$= 28.28$

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If √2=1⋅414, then find the value of :√8+√50+√72+√98

√8+√50+√72+√98Let us simplify the expression,√8+√50+√72+√98=√(2×4)+√(2×25)+√(2×36)+√(2×49)=√2√4+√2√25+√2√36+√2√49=2√2+5√2+6√2+7√2=20√2=20×1.414=28.28

If $\sqrt{2} = 1 \cdot 414,$ then find the value of :
$\sqrt{8} + \sqrt{50} + \sqrt{72} + \sqrt{98}$