For √(2x 5) lt;3 to be defined 2x 5≥ 0 ⇒2x≥ 5⇒ x≥52 nbsp; Squaring both the sides, We get nbsp; 2x 5 lt;9⇒2x lt;14⇒ x lt;7 Taking intersection of ...

215

You visited us 215 times! Enjoying our articles? Unlock Full Access!

Method of Intervals

If √2x-5<3, t...

Question

If $\sqrt{2 x - 5} < 3$ , then $x \in$

(\frac{5}{2}, \infty)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\frac{5}{2}, \infty)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[\frac{5}{2}, 7)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(- \infty, 7)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $[\frac{5}{2}, 7)$
For $\sqrt{2 x - 5} < 3$ to be defined
$2 x - 5 \geq 0 \Rightarrow 2 x \geq 5 \Rightarrow x \geq \frac{5}{2}$

Squaring both the sides, We get
$2 x - 5 < 9 \Rightarrow 2 x < 14 \Rightarrow x < 7$

Taking intersection of both the conditions, we get
$x \in [\frac{5}{2}, 7)$

Suggest Corrections

Similar questions

\sqrt{2 x - 5} < 3

x \in

\frac{x^{10}}{x^{5}} = ?

f (x) = x - 2, x < 3

= 2 x - 5, x \geq 3

Let f(x) = $| x - 3 |$ + $| x - 5 |$

Then f(x) = 2x - 8 if x $\geq$ 5

= 8 - 2x if x $\leq$ 3

f (x) = \frac{2 x - 5}{x + 3},

Join BYJU'S Learning Program