Question

If $\sqrt{3}$ tan $2\theta$ - 3 = 0 then $\theta$ = ?

(a) ${15}^o$ (b) ${30}^o$ (c) ${45}^o$ (d) ${60}^o$

Answer 1

$\sqrt{3}tan2\theta -3=0$

$\sqrt{3}tan2\theta =3$

$tan2\theta =\frac{3}{\sqrt{3}}=\sqrt{3}=tan{60}^o$

$2\theta ={60}^o\Rightarrow \theta =\frac{{60}^o}{2}={30}^o$