If √3 tan 2θ=3 and 0<θ≤90∘θ then
θ = __________________
60∘
45∘
30∘
0
√3 tan 2θ=3
tan 2θ=3√3
tan 2θ=√3
tan 2θ=tan 60∘
Taking inverse on both sides we get,
2θ=60∘
θ=30∘
Hence (C)
If √3 tan 2θ - 3 = 0 then θ = ?
(a) 15o (b) 30o (c) 45o (d) 60o
The value of θ in √3tan2θ - 3 = 0 is