If $\sqrt{5} + \sqrt{2}$ is a root of $3 x^{5} - 4 x^{4} - 42 x^{3} + 56 x^{2} + 27 x - 36 = 0$ , then the rational root is:

\frac{4}{3}

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\frac{3}{4}

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\frac{1}{4}

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- \frac{4}{3}

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Solution

The correct option is A $\frac{4}{3}$
Sum of roots $= - (- 4) / 3 = 4 / 3 = r_{1} + r_{2} + r_{3} + r_{4} + r_{5} = r_{1}$
As irrational roots occur in conjugates.
So $r_{1} = 4 / 3$

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If √5+√2 is a root of 3x5−4x4−42x3+56x2+27x−36=0, then the rational root is:

The correct option is A 43Sum of roots =−(−4)/3=4/3=r1+r2+r3+r4+r5=r1As irrational roots occur in conjugates.So r1=4/3

If $\sqrt{5} + \sqrt{2}$ is a root of $3 x^{5} - 4 x^{4} - 42 x^{3} + 56 x^{2} + 27 x - 36 = 0$ , then the rational root is:

The correct option is A $\frac{4}{3}$
Sum of roots $= - (- 4) / 3 = 4 / 3 = r_{1} + r_{2} + r_{3} + r_{4} + r_{5} = r_{1}$
As irrational roots occur in conjugates.
So $r_{1} = 4 / 3$