Question

If $\sqrt{6}=2.55$, then the value of $\sqrt{\frac{2}{3}}+3\sqrt{\frac{3}{2}}$ is

Answer 1

$\sqrt{6}=2.55$

$\sqrt{\frac{2}{3}}+\sqrt[3]{3\frac{3}{2}}$

$=\frac{\sqrt{6}}{3}+\frac{3\sqrt{6}}{2}$

$=\frac{11\sqrt{6}}{6}=\frac{11\times 2.55}{6}=\frac{9.35}{2}=4.675$ (Answer)