If (√8+i)50=349(a+ib), then find the value of a2+b2.
A
(a2+b2)=9
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B
(a2+b2)=27
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C
(a2+b2)=3
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D
(a2+b2)=1
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Solution
The correct option is A(a2+b2)=9 Given that (√8+i)50=349(a+ib) Taking modulus and squaring both sides, we get (8+1)50=398(a2+b2) or 950=398(a2+b2) or 3100=398(a2+b2) or (a2+b2)=9 Ans: A