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Question

If (8+i)50=349(a+ib), then find the value of a2+b2.

A
(a2+b2)=9
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B
(a2+b2)=27
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C
(a2+b2)=3
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D
(a2+b2)=1
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Solution

The correct option is A (a2+b2)=9
Given that (8+i)50=349(a+ib)
Taking modulus and squaring both sides, we get
(8+1)50=398(a2+b2)
or 950=398(a2+b2)
or 3100=398(a2+b2)
or (a2+b2)=9
Ans: A

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