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Question

If a+ib=x+iy, then possible value of aib is

A
x2+y2
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B
x2+y2
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C
x+iy
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D
xiy
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Solution

The correct option is D xiy
a+ib=x+iy

a+ib=(x+iy)2=x2y2+2ixy

a=x2y2,b=2xy

aib=x2y22ixy

=x2+(iy)22ixy

aib=(xiy)2

aib=xiy

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