If -12-12-12-x- then the value of x is -

The correct option is A 4 √(12+√(12+√(12+....))) = x .........................(1) √(12+x)=x (12+x)=x^2 x^2 x 12=0 (x 4)(x+3)=0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Definition of Relations

If √12+√12+...

Question

If $\sqrt{(12 + \sqrt{12 + \sqrt{12 + . . . .}})} = x$ , then the value of x is ____________.

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Greater than

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$
$\sqrt{12 + \sqrt{12 + \sqrt{12 + . . . .}}} = x$ .........................(1)
$\sqrt{12 + x} = x$
$(12 + x) = x^{2}$
$x^{2} - x - 12 = 0$
$(x - 4) (x + 3) = 0$
$x = 4$ or $x = - 3$
since x is a positive number (eq 1)
$x = 4$

Suggest Corrections

Similar questions

Q. If

{(1 + x - 2 x^{2})}^{6} = 1 + a_{1} x + a_{2} x^{2} + a_{3} x^{3} + \dots + a_{12} x^{12},

then the value of

a_{2} + a_{4} + a_{6} + \dots + a_{12}

will be

(i) Will the value of $2 x^{2} + 12 x + 3$ for x = - 4 be greater than or less than 15?

(ii) If $x^{2}$ is added to $2 x^{2} + 12 x + 3$ and 15 is subtracted from it then evaluate its value at x = -4? [3 MARKS]

Q. If

(1 + x - 2 x^{2})^{6} = 1 + a_{1} x + a_{2} x^{2} + . . . . + a_{12} x^{12}

, then the expression

a_{2} + a_{4} + a_{6} + . . . + a_{12}

has the value.

Q. If

{(1 + x - 2 x^{2})}^{6} = 1 + a_{1} x + a_{2} x^{2} + a_{3} x^{3} + \dots + a_{12} x^{12},

then the value of

a_{2} + a_{4} + a_{6} + \dots + a_{12}

will be

The value of $(2 y - x)^{3}$ is _________.

Join BYJU'S Learning Program

If √(12+√12+√12+....)=x, then the value of x is ____________.

The correct option is A 4√12+√12+√12+....=x.........................(1)√12+x=x(12+x)=x2x2−x−12=0(x−4)(x+3)=0x=4 or x=−3since x is a positive number (eq 1)x=4

If $\sqrt{(12 + \sqrt{12 + \sqrt{12 + . . . .}})} = x$ , then the value of x is ____________.

The correct option is A $4$
$\sqrt{12 + \sqrt{12 + \sqrt{12 + . . . .}}} = x$ .........................(1)
$\sqrt{12 + x} = x$
$(12 + x) = x^{2}$
$x^{2} - x - 12 = 0$
$(x - 4) (x + 3) = 0$
$x = 4$ or $x = - 3$
since x is a positive number (eq 1)
$x = 4$