CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Taking Power of a Power

If √xP=xm, th...

Question

If $\sqrt[n]{x^{P}} = x^{m}$ , then $p$ is equal to:

A

n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

m n

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

\frac{m}{n}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $m n$
$\sqrt[n]{x^{P}} = x^{m} x^{\frac{p}{n}} = x^{m} \Rightarrow \frac{p}{n} = m \Rightarrow p = m n$

Suggest Corrections

thumbs-up

3

Similar questions

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}

\frac{d y}{d x}

x = e^{m^{n p}}

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}, t h e n \frac{d y}{d x}

y = \frac{1}{1 + x^{n - m} + x^{p - m}} + \frac{1}{1 + x^{m - n} + x^{p - n}} + \frac{1}{1 + x^{m - p} + x^{n - p}}

\frac{d y}{d x}

e^{m^{n^{p}}}

x = \frac{y}{(1 + x)^{p}}

p

I_{m, n} = \int_{0}^{1} x^{m} {(log x)}^{n} d x

I_{m, n}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Taking Power of a power

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Taking Power of a Power

Standard VII Mathematics

Join BYJU'S Learning Program

CrossIcon