If -sin x-cos x-0 then sin x-

The correct option is D √(5) 1/2 √(sin x)= cosx sin x=cos^2x sinx = 1 sin^2x sin^2x+sinx 1=0 sinx= 1±√(1^2 4(1)( 1))/2 = 1±√(1+4)/2 = 1±√(5)/2 sinx= 1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Introduction to Trigonometry

If √sin x+cos...

Question

If $\sqrt{s i n x} + c o s x = 0$ then sin x =

\frac{\sqrt{5} + 1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{5} + 1}{8}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{5} - 1}{8}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{\sqrt{5} - 1}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{\sqrt{5} - 1}{2}$

$\sqrt{s i n x} = - c o s x s i n x = c o s^{2} x s i n x = 1 - s i n^{2} x s i n^{2} x + s i n x - 1 = 0 s i n x = \frac{- 1 \pm \sqrt{1^{2} - 4 (1) (- 1)}}{2} = \frac{- 1 \pm \sqrt{1 + 4}}{2} = \frac{- 1 \pm \sqrt{5}}{2} s i n x = \frac{- 1 - \sqrt{5}}{2} o r \frac{\sqrt{5} - 1}{2}$

Suggest Corrections

Similar questions

Q. If

y = \frac{sin x}{1 + \frac{cos x}{1 + \frac{sin x}{1 + \frac{cos x}{1 + \frac{sin x}{1 + . . . . . \infty}}}}}

, then

y^{'} (0)

Q. Solve :
If

\sqrt{sin x} + cos x = 0

, then the value of

sin x

Q. If sin x + cos x = a, then sin x – cos x = __________.

Q. If

cos x + \sqrt{sin x} = 0

, then

x

If $y = s i n x + e^{x}, t h e n \frac{d^{2} x}{d y^{2}} =$

Join BYJU'S Learning Program

If √sinx+cosx=0 then sin x =

The correct option is D √5−12 √sinx=−cosxsinx=cos2xsinx=1−sin2xsin2x+sinx−1=0sinx=−1±√12−4(1)(−1)2=−1±√1+42=−1±√52sinx=−1−√52 or √5−12

If $\sqrt{s i n x} + c o s x = 0$ then sin x =