Question

If $\sqrt{\sqrt{2500}+\sqrt{961}}={\left(x\right)}^2$, then $x$ equals

• A. $81$
• B. $3$
• C. $6561$
• D. $9$

Answer 1

The correct option is B $3$

$\sqrt{\sqrt{2500}+\sqrt{961}}=(x{)}^2$ ...Given

$\Rightarrow$ $\sqrt{50+31}=(x{)}^2$

$\Rightarrow$ $\sqrt{81}=(x{)}^2$

$\therefore$ $x^2=9$

$\therefore$ $x=3$