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Question

If 2x+x41=a+ib, Find the value of a2b2 and 4a2b2

A

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B

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C

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D

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Solution

The correct option is B


2x+(1+x4)
Let 2x+i1+x4=a+ib
Squaring on both sides
2x+1+x4=a2b2+2abi
a2b2=2x
2ab=1+x4
4a2b2=1+x4

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