If -x-y-2-5- then -x-y-

The correct option is C √(2) √(5) We know that, If √(x)+√(y)=√(a)+√(b) then √(x) √(y)=√(a) √(b). Similarly here given, √(x)+√(y)=√(2)+√(5). So, √(x) √(y)=√( ...

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Byju's Answer

Standard X

Mathematics

Addition of Rational Expressions

If √x+√y=√2+√...

Question

If $\sqrt{x} + \sqrt{y} = \sqrt{2} + \sqrt{5}$ , then $\sqrt{x} - \sqrt{y}$ = ___

$\sqrt{2} - \sqrt{3}$

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$\sqrt{2} - \sqrt{5}$

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$\sqrt{5} - \sqrt{2}$

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Can't be determined

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Solution

The correct option is B
$\sqrt{2} - \sqrt{5}$

We know that,

If $\sqrt{x} + \sqrt{y} = \sqrt{a} + \sqrt{b}$ then $\sqrt{x} - \sqrt{y} = \sqrt{a} - \sqrt{b}$ .

Similarly here given, $\sqrt{x} + \sqrt{y} = \sqrt{2} + \sqrt{5}$ .

So, $\sqrt{x} - \sqrt{y} = \sqrt{2} - \sqrt{5}$

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Similar questions

Q. If

\frac{x}{y} = \frac{13}{6}

then find the value of

(i) \frac{3 x + 5 y}{3 x - 5 y} (ii) \frac{2 x^{2} + 5 y^{2}}{2 x^{2} - 5 y^{2}}

Q. a) If

x^{y} = y^{x},

then

(\frac{x}{y})^{\frac{x}{y}}

is equal to:

b) If

\frac{x}{y} = \frac{6}{5}

then

\frac{x^{2} + y^{2}}{x^{2} - y^{2}}

is:

Q. If

\frac{3}{x} - \frac{2}{y} = 5

and

\frac{4}{x} - \frac{5}{y} = 2

, then

\frac{1}{x} - \frac{1}{y} = ?

Where

(x, y \neq 0)

Q. a) If

x^{y} = y^{x},

then

(\frac{x}{y})^{\frac{x}{y}}

is equal to:

b) If

\frac{x}{y} = \frac{6}{5}

then

\frac{x^{2} + y^{2}}{x^{2} - y^{2}}

is: [4 MARKS]

If x : y = 2 : 5 , then find 3x : 5y.

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If √x+√y=√2+√5, then √x−√y = ___

The correct option is B √2−√5 We know that, If √x+√y=√a+√b then √x−√y=√a−√b. Similarly here given, √x+√y=√2+√5. So, √x−√y=√2−√5

If $\sqrt{x} + \sqrt{y} = \sqrt{2} + \sqrt{5}$ , then $\sqrt{x} - \sqrt{y}$ = ___

The correct option is B
$\sqrt{2} - \sqrt{5}$

We know that,

If $\sqrt{x} + \sqrt{y} = \sqrt{a} + \sqrt{b}$ then $\sqrt{x} - \sqrt{y} = \sqrt{a} - \sqrt{b}$ .

Similarly here given, $\sqrt{x} + \sqrt{y} = \sqrt{2} + \sqrt{5}$ .

So, $\sqrt{x} - \sqrt{y} = \sqrt{2} - \sqrt{5}$