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Absolute Value Function

If √2= 1.41...

Question

If $\sqrt{2} = 1.414$ , find the value of $\frac{1}{\sqrt{2} + 1}$

A

1.414

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B

0.327

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C

0.414

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D

1.327

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Solution

The correct option is C $0.414$
$(\frac{1}{\sqrt{2} + 1}) \times (\frac{\sqrt{2} - 1}{\sqrt{2} - 1}) = (\frac{\sqrt{2} - 1}{1}) = 1.414 - 1 = 0.414$

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Similar questions

If $\sqrt{2} = 1.414 t h e n \sqrt{\frac{(\sqrt{2} - 1)}{(\sqrt{2} + 1)}} = ?$

(a) 0.207 (b) 2.414 (c) 0.414 (d) 0.621

\sqrt{2} = 1.414

, then find the value of

\frac{1}{1 - \sqrt{2}}

\sqrt{2} = 1.414

, then find the value of

\frac{1}{3 + \sqrt{2}}

\sqrt{2} = 1.414

\sqrt{\frac{(\sqrt{2} - 1)}{(\sqrt{2} + 1)}}

=?
(a) 0.207
(b) 2.414
(c) 0.414
(d) 0.621

\sqrt{2} = 1.414 then \sqrt{\frac{(\sqrt{2} - 1)}{(\sqrt{2} + 1)}} = ?

(a) 0.207
(b) 2.414
(c) 0.414
(d) 0.621

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