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Question

If 3 cosθ+sinθ=2,then general value of θ is


A

nπ+(1)n π4,nZ

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B

(1)n π4π3,nZ

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C

nπ+π4π3,nZ

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D

nπ+(1)n π4π3,nZ

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Solution

The correct option is D

nπ+(1)n π4π3,nZ


Given equation:3cosθ+sinθ=2 ...(i)This is of form α cosθ+b sin θ=cWhere a=3,b=1 and c=2Let:a=r sin α and b=r cos α.Now,r=a2+b2=(3)2+12=2And,tan α=abtan alpha=31tan α=tanπ3α=π3Putting a=3=r sin α and b=1=r cosα in equation (i),we get:r cosθ sinα+r sinθ cosα=2r sin(θ+α)=22 sin(θ+α)=2sin(θ+π3)=12sin(θ+π3)=cosπ4θ+π3=nπ+(1)n π4,nZθ=nπ+(1)n π4π3,nZ


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