If $□$ ABCD is a trapezium in which side AB $∥$ side DC. If $∠ A = ∠ B = 40^{\circ}$ , what are the measures of the other two angles?

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Solution

$G i v e n : A B C D i s a t r a p e z i u m i n w h i c h A B ∥ D C ∠ A = ∠ B = 40 S i n c e A B ∥ D C ∠ A + ∠ D = 180 (S u m o f i n t e r i o r a n g l e o n t h e s a m e s i d e o f t h e t r a n s v e r s a l i s 180) ⟹ ∠ D = 180 - ∠ A = 180 - 40 = 140 ∴ ∠ D = 140 ∠ B + ∠ C = 180 ⟹ 40 + ∠ C = 180 ∴ ∠ C = 140^{0} H e n c e t h e m e a s u r e o f t w o a n g l e s a r e 140^{0} e a c h$

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Similar questions

□

∠

∠

°

A B C D

¯ ¯¯¯¯¯¯ ¯ A B | | ¯ ¯¯¯¯¯¯¯ ¯ D C

∠ A = ∠ B = 30^{o}

∠ A

∠ B

40^{\circ}

\frac{O C}{O A}

∥

\frac{O C}{O A}

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