If SR = 100 torr and PR = 350 torr then the mole fraction of A in vapour phase and mole fraction of A in liquid phase respectively are:
A
310,29
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B
79,310
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C
29,710
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D
29,310
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Solution
The correct option is D29,310 PQ=SR=PA=100torr and PR=PB=350torr PT=PA+PB=100+350=450torr and PB=P∘B×X′B X′B(vapour phase)=PBPT=350450=79 350=500XB⇒XB=7/10 X′A=1−X′B=29 XA=1−XB=310