If statement (p∨∼r)→(q∧r) is false and statement q is true, then statement p is
A
true.
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B
false.
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C
may be true or false.
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D
none of these.
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Solution
The correct option is C may be true or false. ∵(p∨∼r)→(q∧r) is false ⇒(p∨∼r) is true, and (q∧r) is false Here (q∧r) is false and q is true (given) ⇒r is false again r is false and (p∨∼r) is true ⇒p may be true or false. Ans: C