If stress/strain is $x$ in elastic region and y in the region of yield, then

x = y

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x > y

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x < y

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x = 2 y

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Solution

The correct option is B $x > y$
Looking at the stress- strain curve of the material given in the above figure we observe that
stress/strain value is proportional to slope:
$E l a s t i c$ $r e g i o n$ $s l o p e$ > $R e g i o n$ $o f$ $y i e l d$ $s l o p e$
so, $(\frac{s t r e s s}{s t r a i n})_{e l a s t i c}$ > $(\frac{s t r e s s}{s t r a i n})_{y i e l d}$
Ot, $x > y$ hence option B is correct

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