If sum and product of the slopes of lines represented by ${4 x}^{2} + 2 h x y - {7 y}^{2} = 0$ is equal then h is equal to :

-6

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-2

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-4

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Solution

The correct option is B -2
$4 x^{2} + 2 h \times y - 7 y^{2} = 0$
$a = 4$ $2 h = 2 h$ $b = - 7$
$h = h$

$m_{1} + m_{2} = \frac{- 2 h}{b} = \frac{2 h}{7}$
$\Rightarrow m_{1} m_{2} = \frac{a}{b} = \frac{4}{- 7} = \frac{- 4}{7}$
Given that $m_{1} + m_{2} = m_{1} m_{2}$
$\Rightarrow \frac{2 h}{7} = \frac{- 4}{7}$
$\Rightarrow h = - 2$ .

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If sum and product of the slopes of lines represented by 4x2+2hxy−7y2=0 is equal then h is equal to :

The correct option is B -24x2+2h×y−7y2=0a=4 2h=2h b=−7 h=hm1+m2=−2hb=2h7⇒m1m2=ab=4−7=−47Given that m1+m2=m1m2⇒2h7=−47⇒h=−2 .

If sum and product of the slopes of lines represented by ${4 x}^{2} + 2 h x y - {7 y}^{2} = 0$ is equal then h is equal to :