wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 20i=1( 20Ci120Ci+ 20Ci1)3=k21, then k equals :

A
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
100
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
200
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
400
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 100
(20Ci120Ci+ 20Ci1)=(20Ci121Ci)

nCr+ nCr1= n+1Cr

(20!(i1)!(20i+1))(i!(21i)!21!)=i21

20i=1(20Ci120Ci+20Ci1)3=20i=1(i21)3
=1(21)3(20×(20+1)2)2
=10021
Hence, k=100

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Why Do We Need to Manage Our Resources?
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon