If -i-1- i-nn-1-2- then -i-1-3 i-2-

The correct option is A ∑_i=1^π = 3∑_i=1^π i 2 nbsp;∑_i=1^π 1 = 3 n(n+1)/2 2n = nbsp; n(3n 1)/2 ...

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Variance and Standard Deviation

If ∑i=1π i=nn...

Question

If $π \sum i = 1 i$ = $\frac{n (n + 1)}{2}$ , then $π \sum i = 1 (3 i - 2)$ =

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If $π \sum i = 1 i$ = $\frac{i (i + 1)}{2}$ , then $n \sum i = 1 (3 i - 2)$ =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

I f n \sum i = 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i = 1 (3 i - 2) =

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