If -i-1- i - nn-1-2- then -i-1- 3i - 2 -

∑_i=1^π = 3∑_i=1^π i 2 ∑_i=1^π 1 = 3 n(n+1)/2 2n = n(3n 1)/2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sigma n

If ∑i=1π i = ...

Question

If $π \sum i = 1 i$ = $\frac{n (n + 1)}{2}$ , then $π \sum i = 1 (3 i - 2)$ =

$\frac{n (3 n - 1)}{2}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$\frac{n (3 n + 1)}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n(3n + 2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{n (3 n + 1)}{4}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

If $π \sum i = 1 i$ = $\frac{i (i + 1)}{2}$ , then $n \sum i = 1 (3 i - 2)$ =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

n \sum i - 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i - 1 (3 i - 2) =

I f n \sum i = 1 i = \frac{n (n + 1)}{2}, t h e n n \sum i = 1 (3 i - 2) =

Join BYJU'S Learning Program