Question

If sum of an infinite geometric series is 4/3 and its first term is 3/4 then its common ratio is

Answer 1

$$\begin{gathered} Hi, \\ Herea=\frac{3}{4} \\ commonratio=r \\ andsumofinfiniteseriesofGP=\frac{4}{3} \\ \frac{a}{1-r}=\frac{4}{3} \\ \frac{\frac{3}{4}}{1-r}=\frac{4}{3}\Rightarrow 1-r=\frac{\frac{3}{4}}{\frac{4}{3}}=\frac{9}{16} \\ r=1-\frac{9}{16}=\frac{7}{16} \end{gathered}$$