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Question

If sum of n of a series is given by Sn=3n2+3n, then nth term of the series is

A
3n
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B
3n+10
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C
6n
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D
6n+10
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Solution

The correct option is C 6n
Given : Sn=3n2+3n
Now,
Tn=SnSn1Tn=3n2+3n(3(n1)2+3(n1))Tn=3n2+3n(3(n22n+1)+3n3)Tn=3n2+3n(3n23n)Tn=6n

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