If sum of n terms of a series is given by n n - 1 n - 2 n - 3-4 then the n th term of the series is

The correct option is A n (n + 1) (n + 2) Given S_n = #160;n (n + 1) (n + 2) (n + 3)4 #160; ∴ #160;t_n = S_n S_n 1 = #160;n (n ...

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Arithmetic Mean

If sum of n t...

Question

If sum of n terms of a series is given by $\frac{n (n + 1) (n + 2) (n + 3)}{4}$ then the $n$ th term of the series is

n (n + 1) (n + 2)

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(n + 1) (n + 2) (n + 3)

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\frac{n (n + 1) (2 n + 1)}{6}

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n (4 n^{2} - 1)

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n - \frac{n (n - 1) (n - 2)}{⌊ 3} \cdot 3 + \frac{n (n - 1) (n - 2) (n - 3) (n - 4)}{⌊ 5} \cdot 3^{2} - . . . . .,

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