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Question

If sum of the coefficients in the expansion of (x+3y−2z)n is 128, then greatest coefficient in the expansion (1+x)n is ____

A
7C3
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B
8C5
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C
9C3
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D
5C3
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Solution

The correct option is A 7C3
To find the sum of coefficients, we put all variables as 1.
sum of coeffcients = (1+32)n
= 2n
given, 2n = 128
2n = 27
n = 7,
expansion is (1+x)7
The greatest binomial coefficient of any expansion is coefficient of its middle term.
for expansion of power n, if n is even, then the middle term = ((n/2) + 1)th term
if n is odd, then the middle term = ((n + 1)/2)th term or ((n + 1)/2 + 1)th term
Thus the greatest coefficient of the expansion (1+x)7 is
7C3 or 7C4

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