If sum of the n terms of a sequence is (n-1)2, find the nth term of the sequence.

3n-3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3n-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3n-2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
3n-3

Let $S_{n}$ denote the sum of n terms of a sequence.
$S_{n} = (n - 1)^{2}$
$S_{n - 1} = ((n - 1) - 1)^{2}$
$= (n - 2)^{2}$
Let $T_{n}$ denote the nth term of the sequence.
$T_{n} = (n - 1)^{2} - (n - 2)^{2}$
= 3n-3

Suggest Corrections

Similar questions

Find the sum of 10 terms if the nth term of a sequence is $3^{n}$ - 2.

If the sums of n terms of two arithmetic progressions are in the ratio 3n+5:5n-7, then their n^th terms are in the ratio
(a) 3n-15:n-1
(b) 3n+15:n+1
(c) 5n+13:n+1
(d) 5n-13:n-1

Q. The sum of the first n terms of a sequence is

\frac{n (3 n + 1)}{2}

i) when the sum of the first n terms is 155, show that

3 n^{2} + n - 310 = 0

ii) Solve :

3 n^{2} + n - 310 = 0

Q. If the sum of n terms of an A.P. is 2 n² + 5 n, then its nth term is
(a) 4n − 3
(b) 3 n − 4
(c) 4 n + 3
(d) 3 n + 4

Q. Match the APs to their

n^{th}

terms.

Join BYJU'S Learning Program

If sum of the n terms of a sequence is (n-1)2, find the nth term of the sequence.

The correct option is A 3n-3 Let Sn denote the sum of n terms of a sequence. Sn=(n−1)2 Sn−1=((n−1)−1)2 =(n−2)2 Let Tn denote the nth term of the sequence. Tn=(n−1)2−(n−2)2 = 3n-3

The correct option is A
3n-3

Let $S_{n}$ denote the sum of n terms of a sequence.
$S_{n} = (n - 1)^{2}$
$S_{n - 1} = ((n - 1) - 1)^{2}$
$= (n - 2)^{2}$
Let $T_{n}$ denote the nth term of the sequence.
$T_{n} = (n - 1)^{2} - (n - 2)^{2}$
= 3n-3