If t1 and t2 are roots of the equation t2−2√3t+2=0, then the distance between the points (at21,2at1) and (at22,2at2), where a>0 is
A
2a units
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B
a units
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C
4a units
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D
8a units
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Solution
The correct option is D8a units Given: t2−2√3t+2=0 From sum and product of roots, we get t1+t2=2√3t1t2=2 Now, the distance between the given points =√(at21−at22)2+(2at1−2at2)2=a|t1−t2|√(t1+t2)2+4=a√(t1+t2)2−4t1t2√12+4=4a√12−8=8a units