wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If t5,t10 and t25 are 5th,10th and 25th terms of an AP respectively, then the value of ∣∣ ∣∣t5t10t2551025111∣∣ ∣∣ is

A
40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
E
40
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 0
Let a and d be the first and common difference of an AP.
Then, t5=a+4d
t10=a+9d
and t25=a+24d
Now, Let =∣ ∣t5t10t2551025111∣ ∣
=∣ ∣a+4da+9da+24d51025111∣ ∣
On applying operation
C2C2C1 and C3C3C1, we get
=∣ ∣a+4d5d20d5520100∣ ∣
On expanding along R3, we get
=100d100d=0.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Summation in Determinants
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon