The correct option is C 12πR2T
Given,
Radius of larger drop =R
Surface Tension of liquid =T
Number of identical drops made from larger drop, n=64
Let us suppose, radius of smaller drop is r.
As volume of liquid will remain same.
⇒ Volume of larger drop =n× volume of smaller drop
⇒43πR3=64×43πr3
⇒r=R4
We know that,
Work done = Surface Tension × change in surface area
⇒W=T×ΔA
=T(n×4πr2−4πR2)
=T[64×4π(R4)2−4πR2]
=12πR2T