If $T_{n} = 2 n - 1$ find $S_{3}$

Open in App

Solution

We know $S_{3} = T_{1} + T_{2} + T_{3}$
$T_{n} = 2 n - 1$
$T_{1} = 2 (1) - 1 = 2 - 1 = 1$
$T_{2} = 2 (2) - 1 = 4 - 1 = 3$
$T_{3} = 2 (3) - 1 = 6 - 1 = 5$
$∴ S_{3} = T_{1} + T_{2} + T_{3} = 1 + 3 + 5$
$S_{3} = 9$

Suggest Corrections

Similar questions

T_{n} = 2 n + 3,

S_{3}

In a series if (i) T_n = 2n − 1 find S₅ (ii) T_n = (−1)ⁿ then find (a) S₁ (b) S₂ (c) S₃ (d) S₄

Hence prove that S₁ = S₃ and S₂ = S₄

t_{n} = 2 n

t_{3}

T_{n} = 2 n - 1

t_{n} = 5 - 2 n

t_{n - 1} =

Join BYJU'S Learning Program