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Question

If Tn=2n2+5, find (i) T3 and (ii) T10

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Solution

The given sequence is tn=2n2+5.

The third term t3 can be determined by substituting n=3 in the sequence tn=2n2+5 as follows:

t3=2(3)2+5=(2×9)+5=18+5=23

The tenth term t10 can be determined by substituting n=10 in the sequence tn=2n2+5 as follows:

t10=2(10)2+5=(2×100)+5=200+5=205

Hence, t3=23 and t10=205


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