If $T_{n} = 2 n + 3,$ find $S_{3}$

Open in App

Solution

If $T_{n} = 2 n + 3$ then,

$T_{1} = (2 \times 1) + 3 = 2 + 3 = 5$
$T_{2} = (2 \times 2) + 3 = 4 + 3 = 7$
$T_{3} = (2 \times 3) + 3 = 6 + 3 = 9$

Therefore, $S_{3}$ is the sum of $T_{1}$ , $T_{2}$ and $T_{3}$ that is:

$S_{3} = T_{1} + T_{2} + T_{3} = 5 + 7 + 9 = 21$

Hence, $S_{3} = 21$ .

Suggest Corrections

Similar questions

T_{n} = 2 n - 1

S_{3}

In a series if (i) T_n = 2n − 1 find S₅ (ii) T_n = (−1)ⁿ then find (a) S₁ (b) S₂ (c) S₃ (d) S₄

Hence prove that S₁ = S₃ and S₂ = S₄

t_{n} = 2 n

t_{3}

S_{n} = n^{2} + 2 n,

T_{n}

T_{n} = 2 n - 1

Join BYJU'S Learning Program