Question

If $t_n=4n-3$, then find the first two terms of an A.P.

Answer 1

$t_n=4n-3$
Put n = 1
$\therefore t_1=4\times 1-3$
$=4-3=1$
$\therefore$ First term $\left(t_1\right)=1$
Put n = 2
$\therefore t_2=4\times 2-3$
$=8-3=5$
$\therefore$ Second term $\left(t_2\right)=5$